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Brzeg, Lower Silesian Voivodeship (south-west Poland)
Brzeg, Greater Poland Voivodeship (west-central Poland)
Brzeg, Kuyavian-Pomeranian Voivodeship (north-central Poland)
Brzeg, Lublin Voivodeship (east Poland)
Brzeg, Łódź Voivodeship (central Poland)
Brzeg, Masovian Voivodeship (east-central Poland)
Brzeg, Pomeranian Voivodeship (north Poland)
Brzeg, Świętokrzyskie Voivodeship (south-central Poland)
Brzeg, Gmina Nowy Sącz in Silesian Voivodeship (south Poland)
Brzeg, Gmina Stężyca in Silesian Voivodeship (south Poland)
Brzeg, Gmina Słuck in Silesian Voivodeship (south Poland)
Brzeg, Świdnica County in Lower Silesian Voivodeship (south-west Poland)
Brzeg, Kętrzyn County in Warmian-Masurian Voivodeship
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There exists a functor $F$ satisfying $F(X) \cong M$ for some $M \in \mathbb{C}$-mod
Let $\mathbb{C}$ be the category of complex vector spaces.
If $M, N \in \mathbb{C}$-mod, show there exists a unique functor $F: \mathbb{C}/M \rightarrow \mathbb{C}/N$ such that $F(X) \cong M$, for all $X \in \mathbb{C}$
I was thinking of defining $F$ by $F(X) = M \oplus N$. But I don’t know how to show it is a functor.
A:
Let $f: X\rightarrow M$ be an epimorphism and $g: M\rightarrow N$ be an isomorphism. Then there exists a unique morphism $f’ : X\rightarrow N$ such that $g\circ f’ = f$. Then $f’$ is an epimorphism, since $g$ is an isomorphism. The other direction is similar.
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